Difference between revisions of "Joule-Thomson effect"

From SklogWiki
Jump to: navigation, search
Line 18: Line 18:
 
In terms of the [[second virial coefficient]] at zero [[pressure]] one has
 
In terms of the [[second virial coefficient]] at zero [[pressure]] one has
  
:<math>\mu_{\mathrm JT} = B_2 -T \frac{dB_2}{dT}</math>
+
:<math>\mu_{\mathrm JT}\vert_{p=0} = ^0\!\!\phi = B_2 -T \frac{dB_2}{dT}</math>
 
==References==
 
==References==
 
#[http://jchemed.chem.wisc.edu/Journal/Issues/1981/Aug/jceSubscriber/JCE1981p0620.pdf Thomas R. Rybolt "A virial treatment of the Joule and Joule-Thomson coefficients", Journal of Chemical Education '''58''' pp. 620-624 (1981)]
 
#[http://jchemed.chem.wisc.edu/Journal/Issues/1981/Aug/jceSubscriber/JCE1981p0620.pdf Thomas R. Rybolt "A virial treatment of the Joule and Joule-Thomson coefficients", Journal of Chemical Education '''58''' pp. 620-624 (1981)]
 
[[category: classical thermodynamics]]
 
[[category: classical thermodynamics]]
 
[[category: statistical mechanics]]
 
[[category: statistical mechanics]]

Revision as of 12:20, 12 July 2007

The Joule-Thomson effect is also known as the Joule-Kelvin effect.

Joule-Thomson coefficient

The Joule-Thomson coefficient is given by

\mu_{\mathrm JT} = \left. \frac{\partial T}{\partial p} \right\vert_H

where T is the temperature, p is the pressure and H is the enthalpy.

In terms of heat capacities one has

\mu_{\mathrm JT} C_V = -\left. \frac{\partial E}{\partial V} \right\vert_T

and

\mu_{\mathrm JT} C_p = -\left. \frac{\partial H}{\partial p} \right\vert_T


In terms of the second virial coefficient at zero pressure one has

\mu_{\mathrm JT}\vert_{p=0} = ^0\!\!\phi = B_2 -T \frac{dB_2}{dT}

References

  1. Thomas R. Rybolt "A virial treatment of the Joule and Joule-Thomson coefficients", Journal of Chemical Education 58 pp. 620-624 (1981)