Clausius equation of state: Difference between revisions

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m (Changed comment to be a reference.)
(Corrected T_c to be T_c^3 not T_c^2)
 
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At the [[critical points | critical point]] one has <math>\left.\frac{\partial p}{\partial v}\right|_{T=T_c}=0 </math>, and <math>\left.\frac{\partial^2 p}{\partial v^2}\right|_{T=T_c}=0 </math>, which leads to <ref>For details see the [[Mathematica]] [http://urey.uoregon.edu/~pchemlab/CH417/Lect2009/Clausius%20equation%20of%20state%20to%20evaluate%20a%20b%20c.pdf printout] produced by [http://www.uoregon.edu/~chem/hardwick.html Dr. John L. Hardwick].</ref>
At the [[critical points | critical point]] one has <math>\left.\frac{\partial p}{\partial v}\right|_{T=T_c}=0 </math>, and <math>\left.\frac{\partial^2 p}{\partial v^2}\right|_{T=T_c}=0 </math>, which leads to <ref>For details see the [[Mathematica]] [http://urey.uoregon.edu/~pchemlab/CH417/Lect2009/Clausius%20equation%20of%20state%20to%20evaluate%20a%20b%20c.pdf printout] produced by [http://www.uoregon.edu/~chem/hardwick.html Dr. John L. Hardwick].</ref>


:<math>a =  \frac{27R^2T_c^2}{64P_c}</math>
:<math>a =  \frac{27R^2T_c^3}{64P_c}</math>


:<math>b= v_c - \frac{RT_c}{4P_c}</math>
:<math>b= v_c - \frac{RT_c}{4P_c}</math>

Latest revision as of 09:52, 7 September 2012

The Clausius equation of state, proposed in 1880 by Rudolf Julius Emanuel Clausius [1] [2] is given by (Eq. 1 [3])

[p+aT(v+c)2](v−b)=RT.

where p is the pressure, T is the temperature, v is the volume per mol, and R is the molar gas constant. Tc is the critical temperature and Pc is the pressure at the critical point, and vc is the critical volume per mol.

At the critical point one has ∂p∂v|T=Tc=0, and ∂2p∂v2|T=Tc=0, which leads to [4]

a=27R2Tc364Pc
b=vc−RTc4Pc

and

c=3RTc8Pc−vc

References[edit]