Joule-Thomson effect: Difference between revisions

Revision as of 13:17, 12 July 2007

The Joule-Thomson effect is also known as the Joule-Kelvin effect.

The Joule-Thomson coefficient is given by

μ_{J T} = {\frac{\partial T}{\partial p} |}_{H}

where T is the temperature, p is the pressure and H is the enthalpy.

In terms of heat capacities one has

μ_{J T} C_{V} = - {\frac{\partial E}{\partial V} |}_{T}

and

μ_{J T} C_{p} = - {\frac{\partial H}{\partial p} |}_{T}

μ_{J T} = B_{2} - T \frac{d B_{2}}{d T}

Revision as of 13:09, 12 July 2007 (edit) Carl McBride (talk \| contribs) No edit summary ← Older edit		Revision as of 13:17, 12 July 2007 (edit) (undo) Carl McBride (talk \| contribs) No edit summary Newer edit →
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	In terms of the [[second virial coefficient]] one has		In terms of the [[second virial coefficient]] at zero [[pressure]] one has

	:<math>\mu_{\mathrm JT} = B_2 -T \frac{dB_2}{dT}</math>		:<math>\mu_{\mathrm JT} = B_2 -T \frac{dB_2}{dT}</math>