Ideal gas: Energy

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Revision as of 14:26, 7 June 2007 by Carl McBride (talk | contribs) (New page: The energy of the ideal gas is given by (Hill Eq. 4-16) :<math>E = kT^2 \left. \frac{\partial \ln Q}{\partial T} \right\vert_{V,N}= NkT^2 \frac{d \ln T^{3/2}}{dT} = \frac{3}{2} NkT</m...)
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The energy of the ideal gas is given by (Hill Eq. 4-16)

E=kT2∂lnQ∂T|V,N=NkT2dlnT3/2dT=32NkT

This energy is all kinetic energy, 1/2.kT per degree of freedom. This is because there are no intermolecular forces, thus no potential energy.

References

  1. Terrell L. Hill "An Introduction to Statistical Thermodynamics" 2nd Ed. Dover (1962)