Partition function: Difference between revisions
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the thermodynamic definition of the [[Helmholtz energy function]]. Thus, when <math>N</math> is large, | the thermodynamic definition of the [[Helmholtz energy function]]. Thus, when <math>N</math> is large, | ||
:<math>\left.A\right.=-k_BT\log Z.</math> | :<math>\left.A\right.=-k_BT\log Z(T).</math> | ||
==Connection with thermodynamics== | |||
We have the aforementioned [[Helmholtz energy function]], | |||
:<math>\left.A\right.=-k_BT\log Z(T)</math> | |||
:<math>U=k_B T^{2} \frac{\partial \log Z(T)}{\partial T}</math> | we also have the [[internal energy]], which is given by | ||
:<math>U=k_B T^{2} \left. \frac{\partial \log Z(T)}{\partial T} \right\vert_{N,V}</math> | |||
and the pressure, which is given by | |||
:<math>p=k_B T \left. \frac{\partial \log Z(T)}{\partial V} \right\vert_{N,T}</math>. | |||
These equations provides a link between [[Classical thermodynamics | classical thermodynamics]] and | These equations provides a link between [[Classical thermodynamics | classical thermodynamics]] and | ||
[[Statistical mechanics | statistical mechanics]] | [[Statistical mechanics | statistical mechanics]] | ||
[[category:classical thermodynamics]] | |||
[[category:statistical mechanics]] | |||
Revision as of 14:13, 24 May 2007
The partition function of a system in contact with a thermal bath at temperature is the normalization constant of the Boltzmann distribution function, and therefore its expression is given by
- ,
where is the density of states with energy and the Boltzmann constant.
The partition function of a system is related to the Helmholtz energy function through the formula
This connection can be derived from the fact that is the entropy of a system with total energy . This is an extensive magnitude in the sense that, for large systems (i.e. in the thermodynamic limit, when the number of particles Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle N\to \infty } or the volume ), it is proportional to or . In other words, if we assume large, then
where Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle s(e)} is the entropy per particle in the thermodynamic limit, which is a function of the energy per particle Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle e=E/N} . We can therefore write
Since is large, this integral can be performed through steepest descent, and we obtain
- Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \left.Z(T)\right.=N\exp\{N(s(e_{0})-e_{0}/k_{B}T)\}} ,
where Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle e_{0}} is the value that maximizes the argument in the exponential; in other words, the solution to
This is the thermodynamic formula for the inverse temperature provided Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle e_{0}} is the mean energy per particle of the system. On the other hand, the argument in the exponential is
- Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {1}{k_{B}T}}(TS(E_{0})-E_{0})=-{\frac {A}{k_{B}T}}}
the thermodynamic definition of the Helmholtz energy function. Thus, when Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle N} is large,
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left.A\right.=-k_BT\log Z(T).}
Connection with thermodynamics
We have the aforementioned Helmholtz energy function,
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left.A\right.=-k_BT\log Z(T)}
we also have the internal energy, which is given by
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle U=k_B T^{2} \left. \frac{\partial \log Z(T)}{\partial T} \right\vert_{N,V}}
and the pressure, which is given by
- Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle p=k_B T \left. \frac{\partial \log Z(T)}{\partial V} \right\vert_{N,T}} .
These equations provides a link between classical thermodynamics and statistical mechanics