Partition function: Difference between revisions

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the thermodynamic definition of the [[Helmholtz energy function]]. Thus, when <math>N</math> is large,
the thermodynamic definition of the [[Helmholtz energy function]]. Thus, when <math>N</math> is large,


:<math>\left.A\right.=-k_BT\log Z.</math>
:<math>\left.A\right.=-k_BT\log Z(T).</math>
==Connection with thermodynamics==
We have the aforementioned [[Helmholtz energy function]],


The internal energy is given by
:<math>\left.A\right.=-k_BT\log Z(T)</math>


:<math>U=k_B  T^{2} \frac{\partial \log Z(T)}{\partial T}</math>
we also have the  [[internal energy]], which is given by
 
:<math>U=k_B  T^{2} \left. \frac{\partial \log Z(T)}{\partial T} \right\vert_{N,V}</math>
 
and the pressure, which is given by
 
:<math>p=k_B  T \left. \frac{\partial \log Z(T)}{\partial V} \right\vert_{N,T}</math>.


These equations provides a link between [[Classical thermodynamics | classical thermodynamics]] and  
These equations provides a link between [[Classical thermodynamics | classical thermodynamics]] and  
[[Statistical mechanics | statistical mechanics]]
[[Statistical mechanics | statistical mechanics]]
[[category:classical thermodynamics]]
[[category:statistical mechanics]]

Revision as of 14:13, 24 May 2007

The partition function of a system in contact with a thermal bath at temperature is the normalization constant of the Boltzmann distribution function, and therefore its expression is given by

,

where is the density of states with energy and the Boltzmann constant.

The partition function of a system is related to the Helmholtz energy function through the formula

This connection can be derived from the fact that is the entropy of a system with total energy . This is an extensive magnitude in the sense that, for large systems (i.e. in the thermodynamic limit, when the number of particles Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle N\to \infty } or the volume ), it is proportional to or . In other words, if we assume large, then

where Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle s(e)} is the entropy per particle in the thermodynamic limit, which is a function of the energy per particle Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle e=E/N} . We can therefore write

Since is large, this integral can be performed through steepest descent, and we obtain

Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \left.Z(T)\right.=N\exp\{N(s(e_{0})-e_{0}/k_{B}T)\}} ,

where Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle e_{0}} is the value that maximizes the argument in the exponential; in other words, the solution to

This is the thermodynamic formula for the inverse temperature provided Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle e_{0}} is the mean energy per particle of the system. On the other hand, the argument in the exponential is

Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {1}{k_{B}T}}(TS(E_{0})-E_{0})=-{\frac {A}{k_{B}T}}}

the thermodynamic definition of the Helmholtz energy function. Thus, when Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle N} is large,

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left.A\right.=-k_BT\log Z(T).}

Connection with thermodynamics

We have the aforementioned Helmholtz energy function,

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \left.A\right.=-k_BT\log Z(T)}

we also have the internal energy, which is given by

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle U=k_B T^{2} \left. \frac{\partial \log Z(T)}{\partial T} \right\vert_{N,V}}

and the pressure, which is given by

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle p=k_B T \left. \frac{\partial \log Z(T)}{\partial V} \right\vert_{N,T}} .

These equations provides a link between classical thermodynamics and statistical mechanics