Replica method: Difference between revisions

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:<math>- \beta A_1 (q^{N_0}) = \log Z_1  (q^{N_0})
:<math>- \beta A_1 (q^{N_0}) = \log Z_1  (q^{N_0})
= \log \left( \frac{1}{N_1!}  
= \log \left( \frac{1}{N_1!}  
\int \exp [- \beta (H_{01}(r^{N_1}, q^{N_0}) + H_{11}(r^{N_1}, q^{N_0}) )]~d \{ r \}^{N_1} \right)</math>
\int \exp [- \beta (H_{11}(r^{N_1}) + H_{10}(r^{N_1}, q^{N_0}) )]~d \{ r \}^{N_1} \right)</math>


where <math>Z_1  (q^{N_0})</math> is the fluid [[partition function]], and <math>H_{00}</math>
where <math>Z_1  (q^{N_0})</math> is the fluid [[partition function]], and <math>H_{11}</math>, <math>H_{10}</math> and <math>H_{00}</math>
is the Hamiltonian of the matrix.
are the pieces of the Hamiltonian corresponding to the fluid-fluid, fluid-matrix and matrix-matrix interactions. Assuming that the matrix is a configuration of a given fluid, with interaction hamiltonian <math>H_{00}</math>, we can average over matrix configurations to obtain
Taking an average over matrix configurations gives


:<math>- \beta \overline{A}_1 = \frac{1}{N_0!Z_0} \int \exp [-\beta_0 H_{00} ( q^{N_0})] ~  \log Z_1  (q^{N_0}) ~d \{  q \}^{N_0}</math>
:<math>- \beta \overline{A}_1 = \frac{1}{N_0!Z_0} \int \exp [-\beta_0 H_{00} ( q^{N_0})] ~  \log Z_1  (q^{N_0}) ~d \{  q \}^{N_0}</math>


(Ref.s 1 and 2) An important mathematical trick to get rid of the logarithm inside of the integral is
(see Refs. 1 and 2)


:<math>\log x = \lim_{s \rightarrow 0} \frac{{\rm d}}{{\rm d}s}x^s</math>
:An important mathematical trick to get rid of the logarithm inside of the integral is to use the mathematical identity


one arrives at
:<math>\log x = \lim_{s \rightarrow 0} \frac{{\rm d}}{{\rm d}s}x^s</math>.
 
One can apply this trick to the <math>\log Z_1</math> we want to average, and replace the resulting power <math>(Z_1)^s</math> by <math>s</math> copies of the expression for <math>Z_1</math> ''(replicas)''. The result is equivalent to evaluate <math>\overline{A}_1</math> as
 
:<math> -\beta\overline{A}_1=\frac{Z^{\rm rep}(s)}{Z_0} </math>,
 
where <math>Z^{\rm rep}(s)</math> is the partition function of a mixture with Hamiltonian


:<math>\beta H^{\rm rep} (r^{N_1}, q^{N_0})
:<math>\beta H^{\rm rep} (r^{N_1}, q^{N_0})
= \frac{\beta_0}{\beta}H_{00} (q^{N_0}) + \sum_{\lambda=1}^s
= \frac{\beta_0}{\beta}H_{00} (q^{N_0}) + \sum_{\lambda=1}^s
\left( H_{01}^\lambda (r^{N_1}, q^{N_0}) +  H_{11}^\lambda (r^{N_1}, q^{N_0})\right)</math>
\left( H_{01}^\lambda (r^{N_1}_\lambda, q^{N_0}) +  H_{11}^\lambda (r^{N_1}_\lambda, q^{N_0})\right).</math>


The Hamiltonian written in this form describes a completely equilibrated system
This Hamiltonian describes a completely equilibrated system of <math>s+1</math> components; the matrix and <math>s</math> identical non-interacting copies (''replicas'') of the fluid. Thus the relation between the [[Helmholtz energy function]] of the non-equilibrium partially frozen
of <math>s+1</math> components; the matrix and <math>s</math> identical non-interacting copies (''replicas'') of the fluid.
Thus the relation between the [[Helmholtz energy function]] of the non-equilibrium partially frozen
and the replica (equilibrium) system is given by
and the replica (equilibrium) system is given by



Revision as of 13:05, 24 May 2007

The Helmholtz energy function of fluid in a matrix of configuration in the Canonical () ensemble is given by:

where is the fluid partition function, and , and are the pieces of the Hamiltonian corresponding to the fluid-fluid, fluid-matrix and matrix-matrix interactions. Assuming that the matrix is a configuration of a given fluid, with interaction hamiltonian , we can average over matrix configurations to obtain

(see Refs. 1 and 2)

An important mathematical trick to get rid of the logarithm inside of the integral is to use the mathematical identity
.

One can apply this trick to the we want to average, and replace the resulting power by copies of the expression for (replicas). The result is equivalent to evaluate as

Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle -\beta {\overline {A}}_{1}={\frac {Z^{\rm {rep}}(s)}{Z_{0}}}} ,

where is the partition function of a mixture with Hamiltonian

This Hamiltonian describes a completely equilibrated system of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle s+1} components; the matrix and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle s} identical non-interacting copies (replicas) of the fluid. Thus the relation between the Helmholtz energy function of the non-equilibrium partially frozen and the replica (equilibrium) system is given by

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle - \beta \overline{A}_1 = \lim_{s \rightarrow 0} \frac{{\rm d}}{{\rm d}s} [- \beta A^{\rm rep} (s) ] } .

References

  1. S F Edwards and P W Anderson "Theory of spin glasses",Journal of Physics F: Metal Physics 5 pp. 965-974 (1975)
  2. S F Edwards and R C Jones "The eigenvalue spectrum of a large symmetric random matrix", Journal of Physics A: Mathematical and General 9 pp. 1595-1603 (1976)