Stirling's approximation

From SklogWiki
Revision as of 15:28, 28 March 2007 by 163.117.132.133 (talk)
Jump to navigation Jump to search

James Stirling (1692-1770, Scotland)

lnN!=ln1+ln2+ln3+...+lnN=∑k=1Nlnk


≈∫1Nlnxdx


=[xlnx−x]1N


=NlnN−N+1

Thus, for large N

lnN!≈NlnN−N