1-dimensional hard rods

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A 1-dimensional system having hard sphere interactions. The statistical mechanics of this system can be solved exactly (see Ref. 1).

Canonical Ensemble: Configuration Integral

Consider a system of length L defined in the range [0,L].

Our aim is to compute the partition function of a system of N hard rods of length σ.

Model:

  • External Potential; the whole length of the rod must be inside the range:
V0(xi)={0;σ/2<x<L−σ/2∞;.
Φ(xi,xj)={0;|xi−xj|>σ∞;|xi−xj|<σ

where xk is the position of the center of the k-th rod.

Consider that the particles are ordered according to their label: x0<x1<x2<⋯<xN−1; taking into account the pair potential we can write the canonical partition function (configuration integral) of a system of N particles as:

Z(N,L)N!=∫σ/2L+σ/2−Nσdx0∫x0+σL+σ/2−Nσ+σdx1⋯∫xi−1+σL+σ/2−Nσ+iσdxi⋯∫xN−2+σL+σ/2−Nσ+(N−1)σdxN−1.

Variable change: ωk=xk−(k+12)σ ; we get:

Z(N,L)N!=∫0L−Nσdω0∫ω0L−Nσdω1⋯∫ωi−1L−Nσdωi⋯∫ωN−2L−NσdωN−1.

Therefore:

Z(N,L)N!=(L−Nσ)NN!.
Q(N,L)=(L−Nσ)NΛNN!.

Thermodynamics

Helmholtz energy function

A(N,L,T)=−kBTlogQ

In the thermodynamic limit (i.e. N→∞;L→∞ with ρ=NL, remaining finite):

A(N,L,T)=NkBT[log(NΛL−Nσ)−1].

Equation of state

From the basic thermodynamics, the pressure [linear tension in this case] p can be written as:

p=−(∂A∂L)N,T=NkBTL−Nσ;
Z=pLNkBT=11−η,

where η≡NσL; is the fraction of volume (length) occupied by the rods.

References

  1. Lewi Tonks "The Complete Equation of State of One, Two and Three-Dimensional Gases of Hard Elastic Spheres", Physical Review 50 pp. 955- (1936)
  2. L. van Hove "Quelques Propriétés Générales De L'intégrale De Configuration D'un Système De Particules Avec Interaction", Physica, 15 pp. 951-961 (1949)
  3. L. van Hove, "Sur L'intégrale de Configuration Pour Les Systèmes De Particules À Une Dimension", Physica, 16 pp. 137-143 (1950)