Monte Carlo in the microcanonical ensemble: Difference between revisions

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the potential energy (function of the position coordinates)
the potential energy (function of the position coordinates)


From the partition function in the [[microcanonical ensemble]] we can integrate
Let <math> \left. E  \right. </math> be the total energy of the system.
 
The probability, <math> \left. \Pi \right. </math>  of a given position configuratiom <math> \left. X^{3N} \right. </math>, with potential energy
<math> U \left( X^{3N} \right) </math> can be written as:
 
: <math> \Pi \left( X^{3N}|E \right) \propto
\int d P^{3N} \delta \left[ K(P^{3N})
- \Delta E \right]
</math> ;  (Eq. 1)
where <math> \left. P^{3N} \right. </math> stands for the 3N momenta, and
 
: <math> \Delta E = E - U\left(X^{3N}\right) </math>
 
The Integral in the right hand side of Eq. 1 corresponds to the surface of a 3N-dimensional hyper-sphere of radious
<math> r = \left. 2 m \Delta E \right.  </math> ;
Therefore:
 
:<math> \Pi \left( X^{3N}|E \right) \propto \left[ E- U(X^{3N}) \right]^{3N-1}
</math>
 
 
 
 
 
 
 
 
 
 
 






PEOPLE AT WORK, SORRY FOR ANY INCONVENIENCE
PEOPLE AT WORK, SORRY FOR ANY INCONVENIENCE

Revision as of 15:37, 28 February 2007

Integration of the kinetic degrees of freedom

Considering a system of N identical particles, with total energy H given by:

H=∑i=13Npi22m+U(X3N).

where the first term on the right hand side is the kinetic energy, whereas the second one is the potential energy (function of the position coordinates)

Let E be the total energy of the system.

The probability, Π of a given position configuratiom X3N, with potential energy U(X3N) can be written as:

Π(X3N|E)∝∫dP3Nδ[K(P3N)−ΔE] ; (Eq. 1)

where P3N stands for the 3N momenta, and

ΔE=E−U(X3N)

The Integral in the right hand side of Eq. 1 corresponds to the surface of a 3N-dimensional hyper-sphere of radious r=2mΔE ; Therefore:

Π(X3N|E)∝[E−U(X3N)]3N−1








PEOPLE AT WORK, SORRY FOR ANY INCONVENIENCE