Editing Van der Waals equation of state

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One can re-write the van der Waals equation given above as a [[virial equation of state]] as follows:
One can re-write the van der Waals equation given above as a [[virial equation of state]] as follows:


:<math>Z :=  \frac{pV}{nRT} = \frac{1}{1- \frac{bn}{V}} - \frac{an}{RTV} </math>
:<math>Z :=  \frac{pV}{nRT} = \frac{1}{1- \frac{nb}{V}} - \frac{an}{VRT} </math>


Using the well known [http://mathworld.wolfram.com/SeriesExpansion.html series expansion] <math>(1-x)^{-1} = 1 + x + x^2 + x^3 + ...</math>
Using the well known [http://mathworld.wolfram.com/SeriesExpansion.html series expansion] <math>(1-x)^{-1} = 1 + x + x^2 + x^3 + ...</math>
one can write the first term of the right hand side as <ref>This expansion is valid as long as <math>-1 < x < 1</math>, which is indeed the case for <math>bn/V</math> </ref>:
one can write the first term of the right hand side as <ref>This expansion is valid as long as <math>-1 < x < 1</math>, which is indeed the case for <math>nb/V</math> </ref>:


:<math>\frac{1}{1- \frac{bn}{V}} = 1 +  \frac{bn}{V} +  \left( \frac{bn}{V} \right)^2 +  \left( \frac{bn}{V} \right)^3 + ... </math>
:<math>\frac{1}{1- \frac{nb}{V}} = 1 +  \frac{nb}{V} +  \left( \frac{nb}{V} \right)^2 +  \left( \frac{nb}{V} \right)^3 + ... </math>


Incorporating the second term of the right hand side in its due place leads to:
Incorporating the second term of the right hand side in its due place leads to:


:<math>Z = 1 + \left( b -\frac{a}{RT} \right) \frac{n}{V} +  \left( \frac{bn}{V} \right)^2 + \left( \frac{bn}{V} \right)^3 +  ...</math>.
:<math>Z = 1 + \left( b -\frac{a}{RT} \right) \frac{n}{V} +  \left( \frac{nb}{V} \right)^2 + \left( \frac{nb}{V} \right)^3 +  ...</math>.


From the above one can see that the [[second virial coefficient]] corresponds to
From the above one can see that the [[second virial coefficient]] corresponds to
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:<math>B_{3}(T)=  b^2 </math>
:<math>B_{3}(T)=  b^2 </math>
==Boyle temperature==
==Boyle temperature==
The [[Boyle temperature]] of the van der Waals equation is given by
The [[Boyle temperature]] of the van der Waals equation is given by
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