Stirling's approximation: Difference between revisions

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James Stirling (1692-1770, Scotland)
James Stirling (1692-1770, Scotland)


:<math>\left.\ln N!\right. = \ln 1 + \ln 2 + \ln 3 + ... + \ln N</math>
:<math>\left.\ln N!\right. = \ln 1 + \ln 2 + \ln 3 + ... + \ln N = \sum_{k=1}^N \ln k</math>
 
 
:<math> ~= \sum_{k=1}^N \ln k</math>





Revision as of 15:28, 28 March 2007

James Stirling (1692-1770, Scotland)




Thus, for large N